2x^2-56x+235=0

Solution for 2x^2-56x+235=0 equation:

2x^2-56x+235=0

a = 2; b = -56; c = +235;
Δ = b2-4ac
Δ = -562-4·2·235
Δ = 1256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1256}=\sqrt{4*314}=\sqrt{4}*\sqrt{314}=2\sqrt{314}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-2\sqrt{314}}{2*2}=\frac{56-2\sqrt{314}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+2\sqrt{314}}{2*2}=\frac{56+2\sqrt{314}}{4}
$